思路:设根为1 先dfs一遍把各个节点到根的距离。然后第二遍把根轮换一下,最后比较距离的大小,最小即所求
#include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; #define N 1111111 ll dp[N]; int a[N]; ll sum[N],ans[N]; struct EDGE { int v, next; ll w; } edge[N]; int head[N], e; int n, k, vis[N]; void init() { memset(vis, 0, sizeof(vis)); memset(head, -1, sizeof(head)); e = 0; } void add(int u, int v, int w) { edge[e].v = v; edge[e].w = w; edge[e].next = head[u]; head[u] = e++; } void dfs_dis(int u,int fa) { //printf("%d %d\n",u,fa); sum[u] = a[u]; for(int i = head[u]; i != -1; i = edge[i].next) { int v = edge[i].v; if(v != fa &&!vis[v]) { vis[v]=1; dfs_dis(v, u); sum[u] += sum[v]; dp[u] += dp[v]+sum[v]*edge[i].w; } } } void dfs(int u, int fa,ll val) { ans[u] = dp[u] + val; for(int i = head[u]; i != -1; i = edge[i].next) { int v = edge[i].v; if(v != fa ) { ll tmp = val; tmp += (dp[u]-dp[v]); tmp += ((sum[1]-sum[v])*edge[i].w-sum[v]*edge[i].w); dfs(v, u,tmp); } } } int main () { freopen("house.in","r",stdin); freopen("house.out","w",stdout); scanf("%d",&n); for(int i=1; i<=n; i++) { scanf("%d",&a[i]); } int c,b; ll w; init(); for(int i=1; i<n; i++) { scanf("%d%d%I64d",&c,&b,&w); add(c,b,w); add(b,c,w); } dfs_dis(1,-1); dfs(1,-1,0); int k = 1; for(int i=1; i<=n; i++) { if(ans[k]>ans[i]) { k=i; } } printf("%d %I64d\n",k,ans[k]); }
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时间: 2024-11-08 13:47:57