python 操作 员工信息表
- 要求：
- 可进行模糊查询，语法至少支持下面3种:
select name,age from staff_table where age > 22
select * from staff_table where dept = "IT"
select * from staff_table where enroll_date like "2013"查到的信息，打印后，最后面还要显示查到的条数
- 可创建新员工纪录，以phone做唯一键，staff_id需自增
- 可删除指定员工信息纪录，输入员工id，即可删除
- 可修改员工信息，语法如下:
UPDATE staff_table SET dept="Market" WHERE where dept = "IT"
注意：以上需求，要充分使用函数，请尽你的最大限度来减少重复代码 - 达成要求：
- 查询命令的各单词之间可以有任意数量的空格
- 查询时不设定条件（where语句）也可以执行
- 错误信息高亮显示
- 代码：
#! /usr/bin/env python3
# Author:Jailly
import pickle,re
# 查找
def search(search_condition):
res = [] # 储存查找结果
# where条件存在
if search_condition:
# 三种条件格式
m1 = re.search(r‘age\s+(>|<)\s+(0|([1-9]\d*))‘, search_condition)
m2 = re.search(r‘‘‘
(?P<category>(staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date))
\s+=\s+
(?P<value>.*)
‘‘‘, search_condition, re.X)
m3 = re.search(r‘‘‘
(?P<category>(staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date))
\s+like\s+
(?P<value>[1-9]\d*)
‘‘‘, search_condition, re.X)
# age <|> \d 的情况
if m1:
# 筛选条目
for i in staff_table:
info_dict = dict(zip([‘staff_id‘, ‘name‘, ‘age‘, ‘phone‘, ‘dept‘, ‘enroll_date‘], i))
if eval(m1.group().replace(‘age‘, str(i[2]))):
res.append(info_dict)
# category = \w+ 的情况
elif m2:
# 筛选条目
for i in staff_table:
# 对应信息表中每个条目的字典
info_dict = dict(zip([‘staff_id‘, ‘name‘, ‘age‘, ‘phone‘, ‘dept‘, ‘enroll_date‘], i))
if str(info_dict[m2.group(‘category‘)]) == m2.group(‘value‘).strip():
res.append(info_dict)
# category like \w+ 的情况
elif m3:
for i in staff_table:
info_dict = dict(
zip([‘staff_id‘, ‘name‘, ‘age‘, ‘phone‘, ‘dept‘, ‘enroll_date‘], i)) # 对应每个条目的字典
if info_dict[m3.group(‘category‘)].count(m3.group(‘value‘)) or str(info_dict[m3.group(‘category‘)]).count(str(m3.group(‘value‘))):
res.append(info_dict)
# 条件格式不正确的情况
else:
print(‘\033[1;31mwhere语句格式错误！\033[0m‘)
# 无where条件
else:
for i in staff_table:
info_dict = dict(zip([‘staff_id‘, ‘name‘, ‘age‘, ‘phone‘, ‘dept‘, ‘enroll_date‘], i))
res.append(info_dict)
return res
# 显示查找结果
def show(res, search_categories):
if res:
for i in res:
# 查询所有条目 *
if search_categories.strip() == ‘*‘:
print(‘,‘.join([str(i[‘staff_id‘]), i[‘name‘], str(i[‘age‘]), i[‘phone‘], i[‘dept‘], i[‘enroll_date‘]]))
# 查询指定条目 name,age,...
else:
category_list = search_categories.split(‘,‘)
for j in category_list:
print(i[j.strip()], end=‘,‘)
print()
print(‘\n共查找到%d条记录\n‘ % len(res))
# 保存文件
def save():
with open(‘staff_table.pkl‘, ‘wb‘) as f:
pickle.dump(staff_table, f)
if __name__ == ‘__main__‘:
while 1:
with open(‘staff_table.pkl‘, ‘rb‘) as f:
staff_table = pickle.load(f)
cmd = input(‘command -> ‘)
# 查询指令
search_cmd = re.search(r‘‘‘
^\s*select\s+
(?P<categories>\*|
(
((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date))
(\s*,\s*((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date)))?
(\s*,\s*((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date)))?
(\s*,\s*((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date)))?
(\s*,\s*((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date)))?)
)
\s+from\s+staff_table
(\s+where\s+
(?P<condition>.*))?$‘‘‘,cmd,re.X)
# 添加指令
insert_cmd = re.search(r‘‘‘
^\s*[\w ]+, # 姓名
[1-9]\d*, # 年龄
\d{11}, # 手机号码
[\w ]+, # 部门
((20)|(19))\d{2}-((10)|(11)|(12)|(0[1-9]))-(([0-2][1-9])|(3[01]))$ # 入职日期
‘‘‘,cmd,re.X)
# 删除指令
delete_cmd = re.search(r‘^\d+$‘,cmd)
# 更改指令
update_cmd = re.search(r‘‘‘
^update\s+staff_table\s+set\s+
(?P<category_update>(name)|(age)|(phone)|(dept)|(enroll_date))\s+
=\s+
(‘|")(?P<new_value>.*)(‘|")
(\s+where\s+
(?P<condition>.*))?$
‘‘‘,cmd,re.X)
# 查询
if search_cmd:
search_categories = search_cmd.group(‘categories‘)
search_condition = search_cmd.group(‘condition‘)
res = search(search_condition)
show(res,search_categories)
# 添加
elif insert_cmd:
insert_list = insert_cmd.group().split(‘,‘)
repeat_flag = 0
for i in staff_table:
if insert_list[2] == i[3]:
print(‘\033[1;31m手机号码已存在!\033[0m‘)
repeat_flag = 1
break
else:
insert_list.insert(0,( staff_table[-1][0] + 1 ) )
staff_table.append(insert_list)
save()
print(‘添加成功！‘)
# 删除
elif delete_cmd:
for i in staff_table:
if delete_cmd.group() == str(i[0]):
staff_table.remove(i)
save()
print(‘删除成功！‘)
break
else:
print(‘\033[1;31m该staff_id不存在\033[0m‘)
# 修改
elif update_cmd:
search_condition = update_cmd.group(‘condition‘)
res = search(search_condition)
for i in range(len(staff_table)):
for j in res:
if staff_table[i][0] == j[‘staff_id‘]:
category_update = update_cmd.group(‘category_update‘)
new_value = update_cmd.group(‘new_value‘).strip()
j[category_update] = int(new_value) if category_update == ‘age‘ else new_value
# 保证顺序，不能用list(j.values())
staff_table[i] = list([j[‘staff_id‘],j[‘name‘],j[‘age‘],j[‘phone‘],j[‘dept‘],j[‘enroll_date‘]])
save()
print(‘修改成功！‘)
# 退出
elif cmd == ‘q‘:
break
# 输入格式不正确的情况
else:
print(‘\033[1;31m输入格式错误\033[0m‘)
时间： 2025-01-17 04:25:56