1078 字符串压缩与解压

题目链接：https://pintia.cn/problem-sets/994805260223102976/problems/994805262018265088

题解：

 1 #include <iostream>
 2 #include<cstdio>//getchar所需的头文件
 3 #include<string>
 4 using namespace std;
 5
 6 int main() {
 7     char select;
 8     cin >> select;
 9     getchar();//读入回车键
10     string str;
11     getline(cin, str);
12     if (select == ‘C‘) {
13         int sum = 0;
14         for (int i = 0; i < str.size(); i++) {
15             if (str[i + 1] == str[i]) sum++;
16             else {
17                 if (sum == 0) cout << str[i];
18                 else {
19                     cout << sum + 1 << str[i];
20                 }
21                 sum = 0;
22             }
23         }
24     }
25     else {
26         for (int i = 0; i < str.size(); i++) {
27             int sum = 0;
28             while (1) {
29                 if (str[i] >= ‘0‘&&str[i] <= ‘9‘)
30                     sum = sum * 10 + str[i++] - ‘0‘;//单个字符的个数可能不是一位数
31                 else break;
32             }
33             if (sum == 0) cout << str[i];
34             for (int j = 0; j < sum; j++) {
35                 cout << str[i];
36             }
37         }
38     }
39     return 0;
40 }

原文地址：https://www.cnblogs.com/Gzu_zb/p/9594962.html