脚本案例

打印一个给定的数字的反序，如输入10572，输出27501

1. #!/bin/bash
2. if[ $# -ne 1 ]
3. then
4. echo "Usage: $0 number"
5. echo " I will find reverse of given number"
6. echo " For eg. $0 0123, I will print 3210"
7. exit1
8. fi
9. n=$1
10. rev=0
11. sd=0
12. while[ $n -gt 0]
13. do
14. sd=`expr $n % 10`
15. rev=`expr $rev \* 10 + $sd`
16. n=`expr $n / 10`
17. done
18. echo "Reverse number is $rev"

2、 将/usr/local/test目录下大于100k的文件转移到/tmp目录下：

#!/bin/bash

for FILE in `ls /usr/local/test`
do
    if [ -f $FILE ] ; then
        if [ `ls -l  $FILE | awk `{print $5}` -gt 100000 ] ; then
            mv $FILE  /tmp/
        fi
    fi
done

~~~~~~~~

#!/bin/bash
for FileName in `ls -l  /usr/local/test | awk ‘$5>102400‘ {print $9}`
do
        mv $FileName  /tmp/
done
ls -al  /tmp/
echo  "done!"