Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.
Example:
Input: [1,2,3] Output: 3 Explanation: Only three moves are needed (remember each move increments two elements): [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]
题意:通过最小的移动次数,使所有元素都相等;
思路:
1.对除了最大值之外的所有元素进行加1操作,相当于对最大元素的减1操作;
2.将所有元素都减少到最小值,然后累加计算所有元素与最小值之间的差值;
class Solution(): def minMoves(self, nums): """ :type nums: List[int] :rtype: int """ return sum(nums) - min(nums) * len(nums)
时间: 2024-11-06 09:39:42