Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
Example:
Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4
# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def mergeTwoLists(self, l1, l2): """ :type l1: ListNode :type l2: ListNode :rtype: ListNode """ if not l1 and l2: return l2 if not l2 and l1: return l1 if not l1 and not l2: return [] it1=l1 it2=l2 if it1.val<=it2.val: node=ListNode(it1.val) it1=it1.next else: node=ListNode(it2.val) it2=it2.next ll=node while it1 and it2: if it1.val<=it2.val: node1=ListNode(it1.val) it1=it1.next node.next=node1 node=node1 else: node1=ListNode(it2.val) node.next=node1 node=node1 it2=it2.next if it1: node.next=it1 elif it2: node.next=it2 return ll
原文地址:https://www.cnblogs.com/chiyeung/p/10122525.html
时间: 2024-11-10 03:28:04