POJ1014 Diving bitset优化背包

dp小水题，结果我还WA了一遍qwq

 1 #include <cstdio>
 2 #include <bitset>
 3 #define maxn 120010
 4 using namespace std;
 5 bitset<maxn> bit;
 6 int a[20],tot,T;
 7 void work(){
 8     bit.reset();
 9     bit[0]=1,tot/=2;
10     for(int i=1;i<=6;i++){
11         int k=1;
12         while(a[i]-k>=0){
13             bit|=bit<<(k*i);
14             a[i]-=k;
15             k<<=1;
16             if(bit[tot]){printf("Can be divided.\n\n");return;}
17         }
18         if(a[i]) bit|=bit<<(a[i]*i);
19     }
20     printf("Can‘t be divided.\n\n");
21 }
22 int main(){
23     while(1){
24         tot=0;
25         for(int i=1;i<=6;i++) scanf("%d",&a[i]),tot+=a[i]*i;
26         if(!tot) break;
27         printf("Collection #%d:\n",++T);
28         if(tot&1) printf("Can‘t be divided.\n\n");
29         else work();
30     }
31 }

原文地址：https://www.cnblogs.com/al76/p/9741124.html