BZOJ_1619_[Usaco2008_Nov]_Guarding_the_Farm_保卫牧场_(模拟+bfs)

描述



http://www.lydsy.com/JudgeOnline/problem.php?id=1619

给出一张图每个点的高度,在一个点上安排守卫可以监视周围所有不高于于当前点的点.也就是类似在一个点上灌水,周围(8格)低于它的点都会有水,然后继续...求最少的守卫数.

分析



首先图中的最高点必须是要灌水的,所以就从当前最高的开始宽搜,有水的点标记掉就好了.

 1 #include <bits/stdc++.h>
 2 #define fst first
 3 #define scd second
 4 using namespace std;
 5
 6 typedef pair <int,int> P;
 7 const int maxn=700+5;
 8 struct node{
 9     int x,y,d;
10     node(){}
11     node(int x,int y,int d):x(x),y(y),d(d){}
12     bool operator < (const node &a) const { return d>a.d; }
13 }a[maxn*maxn];
14 int n,m;
15 int go[][2]={-1,-1,-1,0,-1,1,0,-1,0,1,1,-1,1,0,1,1};
16 int Map[maxn][maxn];
17 bool vis[maxn][maxn];
18 P q[maxn*maxn];
19
20 inline int read(int &x){ x=0;int k=1;char c;for(c=getchar();c<‘0‘||c>‘9‘;c=getchar())if(c==‘-‘)k=-1;for(;c>=‘0‘&&c<=‘9‘;c=getchar())x=x*10+c-‘0‘;return x*=k; }
21 inline void solve(){
22     int ans=0;
23     for(int i=1;i<=n*m;i++){
24         if(vis[a[i].x][a[i].y]) continue;
25         ans++;
26         int l,r;
27         q[l=r=1]=P(a[i].x,a[i].y);
28         while(l<=r){
29             P u=q[l++];
30             for(int j=0;j<8;j++){
31                 int dx=u.fst+go[j][0],dy=u.scd+go[j][1];
32                 if(Map[u.fst][u.scd]>=Map[dx][dy]&&!vis[dx][dy]){
33                     vis[dx][dy]=true;
34                     q[++r]=P(dx,dy);
35                 }
36             }
37         }
38     }
39     printf("%d\n",ans);
40 }
41 inline void init(){
42     read(n); read(m);
43     for(int i=1;i<=n;i++)for(int j=1;j<=m;j++) read(Map[i][j]),a[(i-1)*m+j]=node(i,j,Map[i][j]);
44     sort(a+1,a+1+n*m);
45     for(int i=0;i<=m+1;i++) Map[0][i]=Map[n+1][i]=-1;
46     for(int i=0;i<=n+1;i++) Map[i][0]=Map[i][m+1]=-1;
47 }
48 int main(){
49     init();
50     solve();
51     return 0;
52 }

1619: [Usaco2008 Nov]Guarding the Farm 保卫牧场

Time Limit: 5 Sec  Memory Limit: 64 MB
Submit: 708  Solved: 315
[Submit][Status][Discuss]

Description

The
farm has many hills upon which Farmer John would like to place guards
to ensure the safety of his valuable milk-cows. He wonders how many
guards he will need if he wishes to put one on top of each hill. He has a
map supplied as a matrix of integers; the matrix has N (1 < N <=
700) rows and M (1 < M <= 700) columns. Each member of the matrix
is an altitude H_ij (0 <= H_ij <= 10,000). Help him determine the
number of hilltops on the map. A hilltop is one or more adjacent matrix
elements of the same value surrounded exclusively by either the edge of
the map or elements with a lower (smaller) altitude. Two different
elements are adjacent if the magnitude of difference in their X
coordinates is no greater than 1 and the magnitude of differences in
their Y coordinates is also no greater than 1.

农夫JOHN的农夫上有很多小山丘,他想要在那里布置一些保镖(……)去保卫他
的那些相当值钱的奶牛们。
他想知道如果在一座小山丘上布置一名保镖的话,他总共需要招聘多少名保镖。他现在手头有一个用数字矩阵来表示地形的地图。这个矩阵有N行(1 < N
< = 100)和M列( 1 < M < = 70) 。矩阵中的每个元素都有一个值H_ij(0 < = H_ij
< =10,000)来表示该地区的海拔高度。请你帮助他统计出地图上到底有多少个小山丘。
小山丘的定义是:若地图中一个元素所邻接的所有元素都比这个元素高度要小(或它邻接的是地图的边界),则该元素和其周围所有按照这样顺序排列的元素的集合
称为一个小山丘。这里邻接的意义是:若一个元素与另一个横坐标纵坐标和它的横纵坐标相差不超过1,则称这两个元素邻接。 问题名称:guard
输入格式: 第一行:两个由空格隔开的整数N和M 第二行到第N+1行:第I+1行描述了地图上的第I行,有M个由空格隔开的整数:H_ij.
输入样例:(guard.in): 8 7 4 3 2 2 1 0 1 3 3 3 2 1 0 1 2 2 2 2 1 0 0 2 1 1 1 1
0 0 1 1 0 0 0 1 0 0 0 0 1 1 1 0 0 1 2 2 1 1 0 0 1 1 1 2 1 0 输出格式:
第一行:小山丘的个数 输出样例:(guard.out): 3 输出样例解释:
地图上有三个小山丘:每个小山丘的山峰位置分别在左上角(高度为4),右上角(高度为1)和底部(高度为2)。

Input

* Line 1: Two space-separated integers: N and M

* Lines 2..N+1: Line i+1 describes row i of the matrix with M space-separated integers: H_ij

Output

* Line 1: A single integer that specifies the number of hilltops

Sample Input

8 7
4 3 2 2 1 0 1
3 3 3 2 1 0 1
2 2 2 2 1 0 0
2 1 1 1 1 0 0
1 1 0 0 0 1 0
0 0 0 1 1 1 0
0 1 2 2 1 1 0
0 1 1 1 2 1 0

Sample Output

3

HINT

三个山丘分别是:左上角的高度为4的方格,右上角的高度为1的方格,还有最后一行中高度为2的方格.

Source

Silver

时间: 2024-10-10 04:39:17

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