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Sum square difference

Problem 6

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385
= 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

补充两个公式

 证明：倒序相加，

证明：数学归纳法

这都是高中的题目

给出我的python代码：

n = 100
s1 = n*(n+1)/2 # sum of (1..n)1+2+....+n
s2 = n*(n+1)*(2*n+1)/6 # sum of (1+2**2+3**2+...n**2)
print s1**2-s2

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