os.path.join()
函数功能:连接两个或更多的路径名组件
如果各组件名首字母不包含’/’,则函数会自动加上
如果有一个组件是一个绝对路径,则在它之前的所有组件均会被舍弃
如果最后一个组件为空,则生成的路径以一个’/’分隔符结尾
Demo1
import os Path1 = ‘home‘ Path2 = ‘develop‘ Path3 = ‘code‘ Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print (‘Path10 = ‘,Path10) print (‘Path20 = ‘,Path20)
输出如下:
Path10 = homedevelopcode Path20 = home\develop\code
Demo2
import os Path1 = ‘/home‘ Path2 = ‘develop‘ Path3 = ‘code‘ Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print (‘Path10 = ‘,Path10) print (‘Path20 = ‘,Path20)
输出如下:
Path10 = /homedevelopcode Path20 = /home\develop\code
Demo3
import os Path1 = ‘home‘ Path2 = ‘/develop‘ Path3 = ‘code‘ Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print (‘Path10 = ‘,Path10) print (‘Path20 = ‘,Path20)
输出如下:
Path10 = home/developcode Path20 = /develop\code
Demo4
import os Path1 = ‘home‘ Path2 = ‘develop‘ Path3 = ‘/code‘ Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print (‘Path10 = ‘,Path10) print (‘Path20 = ‘,Path20)
输出如下:
Path10 = homedevelop/code Path20 = /code
原文地址:https://www.cnblogs.com/fwl8888/p/10508113.html
时间: 2024-10-08 17:38:46