[leetcode]_Search Insert Position

题目:查找元素target插入一个数组中的位置。

代码:


public int searchInsert(int[] A, int target) {
int len = A.length;
int i;
for(i = 0 ; i < len ; i++){
if(target <= A[i]) break;
}
return i;
}

简单的让人难以置信。吼吼~

[leetcode]_Search Insert Position,布布扣,bubuko.com

时间: 2024-11-04 15:34:52

[leetcode]_Search Insert Position的相关文章

LeetCode——Search Insert Position

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples. [1,3,5,6], 5 → 2 [1,3,5,6], 2

[LeetCode] Search Insert Position [21]

题目 Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples. [1,3,5,6], 5 → 2 [1,3,5,6]

LeetCode: Search Insert Position [034]

[题目] Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples. [1,3,5,6], 5 → 2 [1,3,5,

LeetCode: Search Insert Position 解题报告

Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,

[leetcode]Search Insert Position @ Python

原题地址:https://oj.leetcode.com/problems/search-insert-position/ 题意: Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates

leetcode : Search Insert Position

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →

LeetCode Search Insert Position (二分查找)

题意: 给一个升序的数组,如果target在里面存在了,返回其下标,若不存在,返回其插入后的下标. 思路: 来一个简单的二分查找就行了,注意边界. 1 class Solution { 2 public: 3 int searchInsert(vector<int>& nums,int target) 4 { 5 int L=0, R=nums.size(); 6 while(L<R) 7 { 8 int mid=R-(R-L+1)/2; 9 if(nums[mid]>=t

[LeetCode] Search Insert Position 二分搜索

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →

leetcode Search Insert Position(easy) /java

写easy,心情也很顺畅. 题目的意思是,如果有val,那么返回val的下标.如果没有val,那么找出val应该放在哪里. import java.io.*; import java.util.*; public class Solution { public static int searchInsert(int[] nums, int target) { int r=0; int len=nums.length; if(len==0) return 0; int i,j; i=0; whil