贴一段demo代码，演示channel之间的同步

package main

import (
    "fmt"
    "time"
)

func deskGoRoutine(index int, userChannel chan string, deskChannel chan string) {
    for {
        fmt.Println("deskGoRoutine", index)

        select {
        case info := <-userChannel:
            if info == "userMsg" {
                fmt.Println(info)
                deskChannel <- "deskMsg"
            }
        case <-time.After(time.Second):
            fmt.Println("deskGoRoutine", index, "timeout,continue")
            continue
        }
        time.Sleep(time.Second)
    }
}

func userGoRoutine(index int, deskChannel chan string, userChannel chan string) {
    for {
        fmt.Println("userGoRoutine", index)

        select {
        case info := <-deskChannel:
            if info == "deskMsg" {
                fmt.Println(info)
                userChannel <- "userMsg"
            }
        case <-time.After(time.Second):
            fmt.Println("userGoRoutine", index, "timeout,continue")
            continue
        }
        time.Sleep(time.Second)
    }
}

func main() {

    userChannel := make(chan string)
    deskChannel := make(chan string)

    go userGoRoutine(0, deskChannel, userChannel)
    go deskGoRoutine(0, userChannel, deskChannel)

    userChannel <- "userMsg"

    select {}
}

一个gouRoutine对应一个channel，channel用来同步，如果不加timeout，那么goRoutine在收不到想要的channel数据的时候会死锁，只有加上timeout，才会不断的处理，满足我的需求

贴一段demo代码，演示channel之间的同步