Circle List puzzle
Josephus Story:
there is 41 people , 39 of them have the agreement that: all these 41 people stand as a circle, and one of them count from 1, and the one count to 3, suicide ! and the people next to him count from 1 again, untill all 41 people are dead. But Josephus and his friend don‘t want to die, so they have their location arranged, and become the last 2 person for counting.
// give a number m, n people as a circle and start say a number with 1, the one with number m to say, get out of the circle #include <stdio.h> #include <stdlib.h> typedef struct node { int data; struct node *next; }node; node *create(int n) { node *p = NULL, *head; head = (node*)malloc(sizeof(node)); p = head; node *s; int i = 1; if(0!n) { while(i<=n) { s = (node*)malloc(sizeof(node)); s->data=i++; //initiate the circle list, the first node is 1; the secode node is 2 p->next = s; p=s; } s->next = head->next; } free(head); return s->next; } int main() { int n = 41; //total 41 people_initiate a list with 41 nodes int m = 3; //who count to 3, out of circle _delete the node int i; node *p = create(n); node *temp; m = n%m; //m=2 while(p!=p->next) //if p = p->next, means only 1 node left in the list { for (i=1;i<m-1;i++) { p=p->next; //now p come to the node before the deleting node, only run 1 time } printf("%d", p->next->data); //print the value of the node who going to be deleted temp = p->next; p->next = temp->next; free(temp); p=p->next; // now p point to the node who will start count with 1 } printf("%d\n",p->data); //print the last node of the list return 0; }
时间: 2024-10-08 13:27:08