Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.
Note: if year Y is a leap year, then the 1st leap year is year Y.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow. Each test case contains two positive integers Y and N(1<=N<=10000).
Output
For each test case, you should output the Nth leap year from year Y.
Sample Input
3
2005 25
1855 12
2004 10000
Sample Output
2108
1904
43236
Hint
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; int main() { #ifdef CDZSC_OFFLINE freopen("in.txt","r",stdin); #endif int year,t,n,sum; scanf("%d",&t); while(t--) { sum=0; scanf("%d%d",&year,&n); while(sum<n) { if((year%4==0&&year%100!=0)||(year%400==0)) { sum++; } year++; } printf("%d\n",year-1); } return 0; }