Python字典实现简单的三级菜单

data = {    "北京":{        "昌平":{"沙河":["oldboy","test"],"天通苑":["链接地产","我爱我家"]},        "朝阳":{"望京":["奔驰","陌陌"],"国贸":["CICC","HP"],"东直门":["advent","飞信"]},        "海淀":{}    },    "山东":{        "德州":{},        "青岛":{},        "济南":{}    },    "广东":{        "东莞":{},        "常熟":{},        "佛山":{}    }}exit_flag = Falsewhile not exit_flag:    for i in data:        print(i)    choice_s = input("请输入以上任一省或直辖市名称>>>:")    if choice_s in data:        while not exit_flag:            for i in data[choice_s]:                print("\t",i)            choice_q = input("请输入以上任一市区名称>>>:")            if choice_q in data[choice_s]:                while not exit_flag:                    for i in data[choice_s][choice_q]:                        print("\t\t",i)                    choice_j = input("请输入以上任一街道名称>>>:")                    if choice_j in data[choice_s][choice_q]:                        for i in data[choice_s][choice_q][choice_j]:                            print("\t\t",i)                        last = input("最后一层，按b返回>>>:")                        if last == "b":                            pass                        elif last == "q":                            exit_flag = True                    if choice_j == "b":                        break                    elif choice_j == "q":                        exit_flag = True            if choice_q == "b":                break            elif choice_q == "q":                exit_flag = True

要点：1、字典的层级关系2、break是终止本次循环，pass是什么也不做，一个占位符而已3、巧妙使用exit_flag = False

while not exit_flag: