题目链接:
题意:
给定n q 表示有n个石头 q个询问
下面n个数字给出每个石头的价值
下面n个数字给出每个石头的颜色(用1-n表示)
选出一个子序列使得序列的权值和最大(序列权值计算方式:当这个点的颜色和前面那个点颜色相同时 贡献 value * a, otherwise 贡献 value * b)
下面q行,每行给出 a 和 b的值。
思路:
首先求dp方程 dp[i]表示颜色为i时的最大值 那么 this_point_value = max(dp[j] + b*v[i]) (i!=j) this_point_value = max(dp[i] + a*v[i]) dp[color[i]] = this_point_value;
就是这样。
import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.math.BigInteger; import java.text.DecimalFormat; import java.util.ArrayDeque; import java.util.ArrayList; import java.util.Arrays; import java.util.Collection; import java.util.Collections; import java.util.Comparator; import java.util.Deque; import java.util.HashMap; import java.util.Iterator; import java.util.LinkedList; import java.util.Map; import java.util.PriorityQueue; import java.util.Scanner; import java.util.Stack; import java.util.StringTokenizer; import java.util.TreeMap; import java.util.TreeSet; import java.util.Queue; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; public class Main { int n, q, a, b; int[] v = new int[N], c = new int[N]; long[] dp = new long[N]; int[] pre = new int[N]; long max1, max2; int col1, col2; void up(long val, int col){ if(val>=max1){ if(val>max1){ if(col == col1){ max1 = val; } else { max2 = max1; col2 = col1; max1 = val; col1 = col; } } else if(col!=col1){ max2 = val; col2 = col; } } else if(val >= max2){ if(col == col1)return; max2 = val; col2 = col; } } void work() throws Exception{ n = Int(); q = Int(); for(int i = 1; i <= n; i++)v[i] = Int(); for(int i = 1; i <= n; i++)c[i] = Int(); while(q-->0){ a = Int(); b = Int(); long ans = 0; max1 = -inf64; max2 = -inf64; col1 = 0; col2 = 0; for(int i = 1; i <= n; i++)pre[i] = -1; for(int i = 1; i <= n; i++){ long now = (long)v[i]*b; if(pre[c[i]]!=-1){ now = max(now, dp[c[i]] + (long)a*v[i]); // out.print("now1:"+now); } if(col1!=c[i] && col1!=0)now = max(now, max1 + (long)b*v[i]); else if(col2!=c[i] && col2!=0)now = max(now, max2 + (long)b*v[i]); // out.println(" now2:"+now); up(now, c[i]); if(pre[c[i]] == -1)dp[c[i]] = now; else dp[c[i]] = max(dp[c[i]], now); pre[c[i]] = i; ans = max(ans, now); // out.println(max1+" "+col1); out.println(max2+" "+col2); out.println(now+" "+ans+" ***"); } out.println(ans); } } public static void main(String[] args) throws Exception{ Main wo = new Main(); in = new BufferedReader(new InputStreamReader(System.in)); out = new PrintWriter(System.out); // in = new BufferedReader(new InputStreamReader(new FileInputStream(new File("input.txt")))); // out = new PrintWriter(new File("output.txt")); wo.work(); out.close(); } static int N = 100000+5; static int M = 101; DecimalFormat df=new DecimalFormat("0.0000"); static int inf = (int)1e9; static long inf64 = (long) 1e18; static double eps = 1e-8; static double Pi = Math.PI; static int mod = (int)1e9 + 7 ; private String Next() throws Exception{ while (str == null || !str.hasMoreElements()) str = new StringTokenizer(in.readLine()); return str.nextToken(); } private int Int() throws Exception{ return Integer.parseInt(Next()); } private long Long() throws Exception{ return Long.parseLong(Next()); } private double Double() throws Exception{ return Double.parseDouble(Next()); } StringTokenizer str; static Scanner cin = new Scanner(System.in); static BufferedReader in; static PrintWriter out; /* class Edge{ int from, to, dis, nex; Edge(){} Edge(int from, int to, int dis, int nex){ this.from = from; this.to = to; this.dis = dis; this.nex = nex; } } Edge[] edge = new Edge[M<<1]; int[] head = new int[N]; int edgenum; void init_edge(){for(int i = 0; i < N; i++)head[i] = -1; edgenum = 0;} void add(int u, int v, int dis){ edge[edgenum] = new Edge(u, v, dis, head[u]); head[u] = edgenum++; }/**/ int upper_bound(int[] A, int l, int r, int val) {// upper_bound(A+l,A+r,val)-A; int pos = r; r--; while (l <= r) { int mid = (l + r) >> 1; if (A[mid] <= val) { l = mid + 1; } else { pos = mid; r = mid - 1; } } return pos; } int Pow(int x, int y) { int ans = 1; while (y > 0) { if ((y & 1) > 0) ans *= x; y >>= 1; x = x * x; } return ans; } double Pow(double x, int y) { double ans = 1; while (y > 0) { if ((y & 1) > 0) ans *= x; y >>= 1; x = x * x; } return ans; } int Pow_Mod(int x, int y, int mod) { int ans = 1; while (y > 0) { if ((y & 1) > 0) ans *= x; ans %= mod; y >>= 1; x = x * x; x %= mod; } return ans; } long Pow(long x, long y) { long ans = 1; while (y > 0) { if ((y & 1) > 0) ans *= x; y >>= 1; x = x * x; } return ans; } long Pow_Mod(long x, long y, long mod) { long ans = 1; while (y > 0) { if ((y & 1) > 0) ans *= x; ans %= mod; y >>= 1; x = x * x; x %= mod; } return ans; } int gcd(int x, int y){ if(x>y){int tmp = x; x = y; y = tmp;} while(x>0){ y %= x; int tmp = x; x = y; y = tmp; } return y; } int max(int x, int y) { return x > y ? x : y; } int min(int x, int y) { return x < y ? x : y; } double max(double x, double y) { return x > y ? x : y; } double min(double x, double y) { return x < y ? x : y; } long max(long x, long y) { return x > y ? x : y; } long min(long x, long y) { return x < y ? x : y; } int abs(int x) { return x > 0 ? x : -x; } double abs(double x) { return x > 0 ? x : -x; } long abs(long x) { return x > 0 ? x : -x; } boolean zero(double x) { return abs(x) < eps; } double sin(double x){return Math.sin(x);} double cos(double x){return Math.cos(x);} double tan(double x){return Math.tan(x);} double sqrt(double x){return Math.sqrt(x);} }
时间: 2024-10-24 14:00:48