leetcode342

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leetcode342合理运用位操作判断4的幂

Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example: Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without loops/recursion? 我的解法极其垃圾,建议不要看. public class Solution {

LeetCode191 Number of 1 Bits. LeetCode231 Power of Two. LeetCode342 Power of Four

位运算相关 三道题 231. Power of Two Given an integer, write a function to determine if it is a power of two. (Easy) 分析: 数字相关题有的可以考虑用位运算,例如&可以作为筛选器. 比如n & (n - 1) 可以将n的最低位1删除,所以判断n是否为2的幂,即判断(n & (n - 1) == 0) 代码: 1 class Solution { 2 public: 3 bool isP

leetcode342——Power of Four(C++)

Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example:Given num = 16, return true. Given num = 5, return false. 个人博客:http://www.cnblogs.com/wdfwolf3/ 这道题本身没有难度,这里只是介绍两种思路,当我们判断出它二进制只有1个1的时候,即必为2的幂时,如何进一步判断它是

LeetCode 342

Power of Four Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example: Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without loops/recursion? 1 /**********************