public class Solution { public int FindDuplicate(int[] nums) { if (nums.Count() > 1) { int slow = nums[0]; int fast = nums[nums[0]]; while (slow != fast) { slow = nums[slow]; fast = nums[nums[fast]]; } fast = 0; while (fast != slow) { fast = nums[fast]; slow = nums[slow]; } return slow; } return -1; } }
https://leetcode.com/problems/find-the-duplicate-number/#/description
时间: 2024-12-29 10:13:48