Python Django 调试
>>> class Person(models.Model): ... first_name = models.CharField(max_length = 50) ... last_name = models.CharField(max_length = 50) ... def __unicode__(self): ... return u‘%s %s‘ %(self.first_name ,self.last_name) ... Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/lib/python2.7/site-packages/django/db/models/base.py", line 117, in __new__ kwargs = {"app_label": package_components[app_label_index]} IndexError: list index out of range
模型的定义必须在应用程序中-你看到那里它试图采取 name model_module 错误-这应该有一些像为 project\appname\models.py-project.appname.models,并获得该应用程序的名称,appname 来。在交互式的控制台中,该模块 name 是 ‘main‘,所以它会失败。
为了解决这个问题,你需要在元类 自己指定的 app_label,
>>> from django.db import models >>> class Poll(models.Model): ... question = models.CharField(max_length=200) ... pub_date = models.DateTimeField(‘date published‘) ... class Meta: ... app_label = ‘test‘
解释为什么你可以做到,看看在回溯(traceback)的时候,/usr/lib/python2.7/site-packages/django/db/models/base.py 中提到该文件:
if getattr(meta, ‘app_label‘, None) is None: # Figure out the app_label by looking one level up. # For ‘django.contrib.sites.models‘, this would be ‘sites‘. model_module = sys.modules[new_class.__module__] kwargs = {"app_label": model_module.__name__.split(‘.‘)[-2]} else: kwargs = {}
元类在哪里定义呢?,见上方在该文件中。
时间: 2024-10-14 19:17:10