比较两个时间的大小

    //比较两个时间大小    var myDate = new Date();
    var date = myDate.getFullYear() + ‘-‘ + (myDate.getMonth() + 1) + ‘-‘ + myDate.getDate();

    //选择的时间
    var OneMonth = birth.substring(5, birth.lastIndexOf(‘-‘));
    var OneDay = birth.substring(birth.length, birth.lastIndexOf(‘-‘) + 1);
    var OneYear = birth.substring(0, birth.indexOf(‘-‘));

    //当前的时间
    var TwoMonth = date.substring(5, date.lastIndexOf(‘-‘));
    var TwoDay = date.substring(date.length, date.lastIndexOf(‘-‘) + 1);
    var TwoYear = date.substring(0, date.indexOf(‘-‘));

    var cha = ((Date.parse(OneMonth + ‘/‘ + OneDay + ‘/‘ + OneYear) - Date.parse(TwoMonth + ‘/‘ + TwoDay + ‘/‘ + TwoYear)) / 86400000);

    if (cha >= 1) {
//说明选择的时间比当前时间大;return;
    }

当然了,这种方法有局限性,若时间类型为yyyy/MM/dd则先需要将转换年月日分割的标识变更即可;写这些,不为别的,只想在我的代码之路上留下印记,日后方便自已,方便他人;