LeetCode 223. 矩形面积(Rectangle Area)

223. 矩形面积
223. Rectangle Area

题目描述
在二维平面上计算出两个由直线构成的矩形重叠后形成的总面积。

每个矩形由其左下顶点和右上顶点坐标表示，如图所示。

LeetCode223. Rectangle Area中等

示例:

输入: -3, 0, 3, 4, 0, -1, 9, 2
输出: 45

说明: 假设矩形面积不会超出 int 的范围。

Java 实现

class Solution {
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int area1 = (C - A) * (D - B), area2 = (G - E) * (H - F);
        int left = Math.max(A, E);
        int right = Math.min(C, G);
        int bottom = Math.max(B, F);
        int top = Math.min(D, H);
        int overlap = 0;
        if (right > left && top > bottom) {
            overlap = (right - left) * (top - bottom);
        }
        return area1 + area2 - overlap;
    }
}

相似题目

• 836. 矩形重叠 Rectangle Overlap

参考资料

• https://leetcode.com/problems/rectangle-area/
• https://leetcode-cn.com/problems/rectangle-area/

原文地址：https://www.cnblogs.com/hglibin/p/10994448.html