Immediate Decodability

An encoding of a set of symbols is said to be immediately decodable if no code for one symbol is the prefix of a code for another symbol. We will assume for this problem that all codes are in binary, that no two codes within a set of codes are the
same, that each code has at least one bit and no more than ten bits, and that each set has at least two codes and no more than eight.

Examples: Assume an alphabet that has symbols {A, B, C, D}

The following code is immediately decodable:

A:01 B:10 C:0010 D:0000

but this one is not:

A:01 B:10 C:010 D:0000 (Note that A is a prefix of C)

Input

Write a program that accepts as input a series of groups of records from a data file. Each record in a group contains a collection of zeroes
and ones representing a binary code for a different symbol. Each group is followed by a single separator record containing a single 9; the separator records are not part of the group. Each group is independent of other groups; the codes in one group are not
related to codes in any other group (that is, each group is to be processed independently).

Output

For each group, your program should determine whether the codes in that group are immediately decodable, and should print a single output line
giving the group number and stating whether the group is, or is not, immediately decodable.

The Sample Input describes the examples above.

Sample Input

01
10
0010
0000
9
01
10
010
0000
9

Sample Output

Set 1 is immediately decodable
Set 2 is not immediately decodable

题意：对于二进制编码，找是否有有一个二进制编码是另一个的前缀，如果有输出 not  immediately，没有输出 immediately。

思路：暴力比较，也可以用字典树，改天更新

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <algorithm>
#include <iostream>
using namespace std;
int cmp(char *str1,char *str2)
{
    int i;
    int len,len1,len2;
    len1=strlen(str1);
    len2=strlen(str2);
    len=min(len1,len2);
    for(i=0;i<len;i++)
    {
        if(str1[i]!=str2[i])
            return 1;
    }
    return 0;
}
int main()
{
    char str[20][20];
    int n,i,j;
    int t=1;
    int flag;
    while(scanf("%s",str[0])==1)
    {
        n=1;
        flag=0;
        while(scanf("%s",str[n])&&str[n][0]!='9')
        {
            n++;
        }
        for(i=0;i<n;i++)
        {
            for(j=i+1;j<n;j++)
            {
                if(cmp(str[i],str[j])==0)
                {
                    flag=1;
                    break;
                }
            }
            if(flag)
                    break;
        }
        if(!flag)
            printf("Set %d is immediately decodable\n",t++);
        else
            printf("Set %d is not immediately decodable\n",t++);
    }
    return 0;
}