A+B Coming
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6464 Accepted Submission(s): 4248
Problem Description
Many classmates said to me that A+B is must needs.
If you can’t AC this problem, you would invite me for night meal. ^_^
Input
Input may contain multiple test cases. Each case contains A and B in one line.
A, B are hexadecimal number.
Input terminates by EOF.
Output
Output A+B in decimal number in one line.
Sample Input
1 9 A B a b
Sample Output
10 21 21
这个题无语……表示以前见过 但是忘了!!
知识一:
将十六进制转换为十进特例:
AB转换为dec;
0xAB
= 0x0A * 16 + 0x0B
= 10 * 16 + 11
= 171
c 输入十六进制和八进制方法:
scanf(“%x %x”,&a,&b);
scanf(“%o %o”,&a,&b);
c++ 方法:
cin>>hex>>a>>b;
cin>>oct>>a>>b;
输出与之类似 ,
败了 看来要请吃饭了!
AC:
#include<iostream> using namespace std; int main() { int a,b; while(cin>>hex>>a>>b) cout<<dec<<a+b<<endl; return 0; }
时间: 2024-10-08 14:01:34