4. Father's Impact on a Child's Language Development 父亲对孩子语言发展的影响

4. Father‘s Impact on a Child‘s Language Development 父亲对孩子语言发展的影响
①Im families with two working parents,father may have more impact on a child‘s language development than mothers,a new study suggests.

②Researchers recruited 92 families from 11 child care centers before their children were a year old,interviewing each to establish income,level of education and child care arrangements.Overall,It was a group of well-educated middle-class families,with married parents both living in the home.
③when the children were 2,researches videotaped them at home in free-play sessions with both parents,recording all of their speech.The study will appear in the November issue of The Journal of Applied Developmental Psychology.
④The scientists measured the total number of utterance of the parents,the number of different words they used ,the complexity of their sentences and other aspects of their speech.On average,fathers spoke less than mothers did,but they not differ in the length of utterances or proportion of questions asked.
⑤Finally,the researches analyzed the children speech’s at age 3,using a standard language test.The only predictors of high scores on the test were the mother’s level of education,the quality of child care and the number of different words the father used.
⑥The researchers are unsure why the father’s speech,and not the mother’s,had an effect.
⑦"It’s well established that the mother’s language does have an impact,"said Nadya Pancsofar,the lead author of the study.It could be that the high-functioning mothers in the study had already had a strong influence on their children’s speech development,Ms Pancsofar said,"or it may be that mothers are contributing in a way we didn’t measure in the study."

4. Father's Impact on a Child's Language Development 父亲对孩子语言发展的影响

原文地址:https://www.cnblogs.com/larken/p/10437273.html

时间: 2024-09-27 00:21:18

4. Father's Impact on a Child's Language Development 父亲对孩子语言发展的影响的相关文章

递推+高精度 UVA 10497 Sweet Child Makes Trouble(可爱的孩子惹麻烦)

题目链接 题意: n个物品全部乱序排列(都不在原来的位置)的方案数. 思路: dp[i]表示i个物品都乱序排序的方案数,所以状态转移方程.考虑i-1个物品乱序,放入第i个物品一定要和i-1个的其中一个交换位置,即:考虑i-2个物品乱序,第i-1个和第i个首先在原来的位置,两种方法使得乱序,一种和第i个交换(不能和前i-2个交换,那样成dp[i-1]),还有一种是第i个先和第i-1个交换,再和前i-2个其中一个交换,即,仔细想想,这个和dp[i-1]是不同的交换方法. 另外: 还有二维的dp写法,

Java代码输出是“father”还是“child”(一)

1.实例 /** * 以下代码输出的结果是 */ package com.you.model; /** * @author YouHaidong * 输出的结果 */ public class FatherChild { /** * @param args */ @SuppressWarnings("static-access") public static void main(String[] args) { Father father = new Father(); Father

Java代码输出是“father”还是“child”(二)

1.实例 /** * 以下代码输出的结果是 */ package com.you.model; /** * @author YouHaidong * 输出的结果 */ public class FatherChild { /** * @param args */ @SuppressWarnings("static-access") public static void main(String[] args) { Father father = new Father(); Father

Codeforces 437C The Child and Toy(贪心)

题目连接:Codeforces 437C The Child and Toy 题目大意:孩子有一个玩具,有n个部件组成,m条绳子组成,每条绳子连接两个部件.小孩比较顽皮,要将玩具拆成不可分割的部件,每次剪断一条绳子的代价是该绳子连接的两个部件的权值中较小的值.问说最小的总代价是多少. 解题思路:以为每条边都是要被剪断的,所以将节点按照代价值从大到小排序,每次拿掉权值大的点,与该点连接并且还未剪断的边均用另外点的权值. #include <cstdio> #include <cstring

fanyi1

This article was downloaded by: [130.108.121.217]On: 07 October 2014, At: 02:50Publisher: RoutledgeInforma Ltd Registered in England and Wales Registered Number: 1072954Registered office: Mortimer House, 37-41 Mortimer Street, London W1T 3JH,UKMarria

js addEventListener removeEventListener

p.p1 { margin: 0.0px 0.0px 0.0px 0.0px; font: 17.0px "Helvetica Neue"; color: #454545 } li.li2 { margin: 0.0px 0.0px 0.0px 0.0px; font: 12.0px ".PingFang SC"; color: #454545 } li.li3 { margin: 0.0px 0.0px 0.0px 0.0px; font: 12.0px &quo

并发包(转) http://blog.csdn.net/he90227/article/details/52788981

1. 各种同步控制工具的使用 1.1 ReentrantLock ReentrantLock感觉上是synchronized的增强版,synchronized的特点是使用简单,一切交给JVM去处理,但是功能上是比较薄弱的.在JDK1.5之前,ReentrantLock的性能要好于synchronized,由于对JVM进行了优化,现在的JDK版本中,两者性能是不相上下的.如果是简单的实现,不要刻意去使用ReentrantLock. 相比于synchronized,ReentrantLock在功能上

数组splay ------ luogu P3369 【模板】普通平衡树(Treap/SBT)

二次联通门 : luogu P3369 [模板]普通平衡树(Treap/SBT) #include <cstdio> #define Max 100005 #define Inline __attri\ bute__( ( optimize( "-O2" ) ) ) Inline void read (int &now) { now = 0; register char word = getchar (); bool temp = false; while (wor

须知的css——margin不重叠的情形

margin重叠 摘自css2.1规范中文版 CSS中,两个或者多个盒(可能但不一定是兄弟)的相邻的margin会被结合成一个margin.Margin按这种方式结合叫重叠(collapse),产生的结合的margin叫做重叠margin. margin重叠的计算规则 摘自css2.1规范中文版 当两个或者更多的margin合并时,产生的margin宽度为合并margin宽度中的最大值.至于负margin,就从正相邻margin的最大值中减去负相邻margin的绝对值的最大值.如果没有正marg