题目:算日期
输入一个日期,输出这是这一年的第几天。(题目中没有给出闰年的定义)
输入 20131231
输出 365
#include <stdio.h> //判断是否为闰年 int isleapyear(int year) { if(year%4==0 && year%100!=0 || year%400==0) return 1; return 0; } int main() { int year,month,day; char a[8]; int leap[13]={0,31,60,91,121,152,182,213,244,274,305,335,366}; int noleap[13]={0,31,59,90,120,151,181,212,243,273,304,334,365}; while(scanf("%s",a)!=EOF){ year = (a[3]-'0')+(a[2]-'0')*10+(a[1]-'0')*100+(a[0]-'0')*1000; month = (a[5]-'0')+(a[4]-'0')*10; day = (a[7]-'0')+(a[6]-'0')*10; if(isleapyear(year)){ printf("%d\n",leap[month-1]+day); }else{ printf("%d\n",noleap[month-1]+day); } } return 0; }
测试结果,可能不周全,欢迎查漏补缺,
时间: 2024-10-23 19:01:26