快速幂取模运算
1 #include <iostream> 2 using namespace std; 3 4 int main() 5 { 6 int a, b, c; 7 long long ans = 1, base = a; 8 9 a %= c; 10 while (b) { 11 if (b & 1) { 12 ans = (ans * base) % c; 13 } 14 base = (base * base) % c; 15 b >>= 1; 16 } 17 cout << ans; 18 19 return 0; 20 }
辗转相除法求最大公约数
1 #include <iostream> 2 #include <algorithm> 3 using namespace std; 4 5 void Swap (long long *a, long long *b) 6 { 7 long long temp; 8 temp = *a; 9 *a = *b; 10 *b = temp; 11 } 12 13 int main() 14 { 15 long long Max, Min; 16 long long r; 17 long long muy; 18 19 cin >> Max >> Min; 20 if (Max < Min) 21 Swap(&Max, &Min); 22 23 muy = Max * Min; 24 while (Min) { 25 r = Max % Min; 26 Max = Min; 27 Min = r; 28 } 29 cout << muy / Max; //Max为最大公约数 30 31 return 0; 32 }
时间: 2024-12-27 21:39:36