linux $* 和[email protected]

$* 将命令后面的参数理解为一个类似为字符串,[email protected]理解为多个单个的参数,类似理解成数据

[[email protected] test]#  ./test4.sh jskd sj21 2 2 1 34
Using the $* method :jskd sj21 2 2 1 34
Using the [email protected] method :jskd sj21 2 2 1 34
------------------------------
$* parameter # = jskd sj21 2 2 1 34
[email protected] Parameter #count = jskd
[email protected] Parameter #count = sj21
[email protected] Parameter #count = 2
[email protected] Parameter #count = 2
[email protected] Parameter #count = 1
[email protected] Parameter #count = 34
[[email protected] test]# 
#!/bin/bash
#testing $* and [email protected]
echo "Using the \$* method :$*"
echo "Using the \[email protected] method :[email protected]"
echo ------------------------------

for param in "$*"
do
        echo "\$* parameter #$count = $param "
        count=$[ $count + 1 ]
done
count=1
for param in "[email protected]"
do
        echo "\[email protected] Parameter #count = $param"
        count=$[ $count + 1 ]
done
~      

if [ str1 = str2 ]       当两个串有相同内容、长度时为真 
if [ str1 != str2 ]      当串str1和str2不等时为真 
if [ -n str1 ]       当串的长度大于0时为真(串非空) 
if [ -z str1 ]        当串的长度为0时为真(空串) 
if [ str1 ]         当串str1为非空时为真

时间: 2024-07-31 14:26:36

linux $* 和[email protected]的相关文章

$*和[email protected]之间区别代码分析

#!/bin/bash set 'apple pie' pears peaches for i in $*           /*单引号被去掉,循环单个字符输出*/ do echo $i done [[email protected] Ex_14.02-14.31]# sh 14-14-1 apple pie pears peaches -------------------------------------------------------------- #!/bin/bash set

[email protected]一个高效的配置管理工具--Ansible configure management--翻译(六)

无书面许可请勿转载 高级playbook Finding files with variables All modules can take variables as part of their arguments by dereferencing them with {{ and }} . You can use this to load a particular file based on a variable. For example, you might want to select a

【转载】 ERROR 1045 (28000): Access denied for user [email protected] (using password: NO)

来自:http://www.jb51.net/LINUXjishu/10981.html 错误描述: Mysql中添加用户之后可能出现登录时提示ERROR 1045 (28000): Access denied for user的错误.删除user.user中值为NULL的,或更新NULL为test 1)delete from user where user is NULL 2)update user set user='test' where user is NULL.意外的情况: 如果上述方

[[email protected]] Omit catch error block if not needed

From [email protected], you can omit catch error block. Before: try { throw new Error('whatever'); } catch(err) { console.log(err) } Now: try { throw new Error('whatever'); } catch { console.log("error happened") } It is just a syntax sugar, if

[email protected]动态代理-类加载器

一.测试单元     概述:用于测试JAVA代码的工具类,已内置在Eclipse中;     格式:         1.在方法的上面添加@Test;         2.对被测试的方法的要求:权限-public;返回值-void;参数-空参         [email protected]:在@Test标注的方法前执行,可以用于初始化;           @After:在@Test标注的方法后执行,可以用于释放资源; 二.注解     概述:java的一种数据类型,和类/接口在同一级别  

git push报错error: failed to push some refs to '[email protected]:

$ git push -u origin master To [email protected]:xxx/xxx.git ! [rejected] master -> master (fetch first) error: failed to push some refs to '[email protected]:xxx/xxx.git' hint: Updates were rejected because the remote contains work that you do hint:

Https方式使用[email protected]设置密码的方式

62561_silentboy Zoker3 years ago member https方式每次都要输入密码,按照如下设置即可输入一次就不用再手输入密码的困扰而且又享受https带来的极速 设置记住密码(默认15分钟): git config --global credential.helper cache 如果想自己设置时间,可以这样做: git config credential.helper 'cache --timeout=3600' 这样就设置一个小时之后失效 长期存储密码: git

mysql Access denied for user [email protected]错误解决方法总结(转)

mysql Access denied for user [email protected]错误解决方法总结(转) mysql Access denied for user \'root\'@\'localhost\'”解决办法总结,下面我们对常见的出现的一些错误代码进行分析并给出解决办法,有需要的朋友可参考一下. 错误代码 1045 Access denied for user 'root'@'localhost' (using password:YES) 解决办法是重新设置root用户密码,

解决[email protected]'s password:localhost:permission denied,please try again

背景:在装完Hadoop及jdk之后,在执行start-all.sh的时候出现 [email protected]'s password:localhost:permission denied,please try again 可是,我记得当时设置的密码是对的,无论怎么输都不对 解决方法:在出现上述问题后,输入 [cpp] view plain copy sudo passwd 然后,会输入新的密码,设置之后,再重新格式化一下namenode,最后执行start-all.sh,OK. 解决[em

CenOS7.1 [email protected]:1.service: control process exited, code=exited status=2

参考:http://www.cnblogs.com/gaohong/p/4829206.html 报错细节: [email protected]:1.service: control process exited, code=exited status=2 主要原因:因为异常关机导致临时文件生成错误 解决办法:删除vncserver产生的临时用户文件X1([email protected]:1.service对应的)