744. Find Smallest Letter Greater Than Target 找到大于目标的最小的字母

Given a list of sorted characters letters containing only lowercase letters, and given a target letter target, find the smallest element in the list that is larger than the given target.

Letters also wrap around.  For example, if the target is target = ‘z‘ and letters = [‘a‘, ‘b‘], the answer is ‘a‘.

Examples:

Input:letters = ["c", "f", "j"]
target = "a" Output: "c"

Input:letters = ["c", "f", "j"]
target = "c" Output: "f"

Input:letters = ["c", "f", "j"]
target = "d" Output: "f"

Input:letters = ["c", "f", "j"]
target = "g" Output: "j"

Input:letters = ["c", "f", "j"]
target = "j" Output: "c"

Input:letters = ["c", "f", "j"]
target = "k" Output: "c"

给定一个只包含小写字母的已排序字符的列表，并给出目标字母目标，找到列表中比给定目标大的最小元素。

字母是可以环绕的。例如，如果target是target =‘z‘，letters = [‘a‘，‘b‘]，则答案是‘a‘。

/**
 * @param {character[]} letters
 * @param {character} target
 * @return {character}
 */
var nextGreatestLetter = function(letters, target) {
   for (let i in letters) {
        if (letters[i] > target) {
            return letters[i];
        }
    }
    return letters[0]; 
};

来自为知笔记(Wiz)