uva101-木块问题

此题为小白书里数据结构基础的线性表训练

翻译请戳 http://luckycat.kshs.kh.edu.tw/

解题思路

开个二维数组模拟整个过程就行了。

注意题目中提到的不理会的情况。测试数据不会很刁难。

这个模拟还是挺烦的。。。

代码：

#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std;
const int MAX_LEN = 25;
typedef struct pos {
    int x, y;
}npos;
int nBlock;
int stack[MAX_LEN][MAX_LEN];
npos found(int index)
{
    for(int i=0; i<nBlock; i++) {
        for(int j=0; j<MAX_LEN; j++)
            if(stack[i][j] == index) {
                npos temp;
                temp.x = i; temp.y = j;
                return temp;
            }
            else if(stack[i][j] == -1) break;
    }
}
int count(int index)
{
    npos now = found(index);
    int count = 0;
    for(int j=now.y+1; stack[now.x][j]>=0; j++,count++);
    return count;
}
void initPos(int index)
{
    npos now = found(index);
 //   int sum = count(index);
    for(int j=now.y+1; stack[now.x][j]>=0; j++) {
        int temp = stack[now.x][j];
        stack[temp][0] = temp;
        stack[now.x][j] = -1;
    }
}
int main()
{
    while(scanf("%d", &nBlock) == 1) {
        char order[20];
        int a, b;
        memset(stack, -1, sizeof(stack));
        for(int i=0; i<nBlock; i++) stack[i][0] = i;
        getchar();
        gets(order);
        while(strstr(order, "quit") == NULL) {
            if(strstr(order, "move")!=NULL && strstr(order, "onto")!=NULL) {
                sscanf(order, "move %d onto %d", &a, &b);
            //    initPos(a); initPos(b);
                npos temp1 = found(b);
                npos temp2 = found(a);
                if(temp1.x != temp2.x) { initPos(a);initPos(b); }
                if(temp1.x != temp2.x) {
                    stack[temp1.x][temp1.y+1] = a;
                    stack[temp2.x][temp2.y] = -1;
                }
            }
            if(strstr(order, "move")!=NULL && strstr(order, "over")!=NULL) {
                sscanf(order, "move %d over %d", &a, &b);
            //    initPos(a);
                int temp = count(b);
                npos tempPos = found(b);
                npos tempa = found(a);
                if(tempPos.x != tempa.x) initPos(a);
                if(tempPos.x != tempa.x) {
                    stack[tempPos.x][tempPos.y+temp+1] = a;
                    stack[tempa.x][tempa.y] = -1;
                }
            }
            if(strstr(order, "pile")!=NULL && strstr(order, "onto")!=NULL) {
                sscanf(order, "pile %d onto %d", &a, &b);
            //    initPos(b);
            //  int temp = count(a);
                npos tempa = found(a);
                npos tempb = found(b);
                if(tempa.x != tempb.x) initPos(b);
                int i, j;
                for(j=tempa.y,i=tempb.y+1; tempa.x != tempb.x&&stack[tempa.x][j]>=0; j++,i++) {
                    stack[tempb.x][i] = stack[tempa.x][j];
                    stack[tempa.x][j] = -1;
                }
            }
            if(strstr(order, "pile")!=NULL && strstr(order, "over")!=NULL) {
                sscanf(order, "pile %d over %d", &a, &b);
                int countb = count(b);
            //  int countb = count(b);
                npos tempa = found(a);
                npos tempb = found(b);
                int i, j;
                for(j=tempa.y,i=tempb.y+countb+1; tempa.x != tempb.x && stack[tempa.x][j]>=0; j++,i++) {
                    stack[tempb.x][i] = stack[tempa.x][j];
                    stack[tempa.x][j] = -1;
                }
            }
            gets(order);
        }
        for(int i=0; i<nBlock; i++) {
            int j = 0;
            cout << i << ":";
            while(stack[i][j]>=0) {
                cout << " " << stack[i][j]; j++;
            }
            if(i != nBlock) cout << endl;
        }
    }
    return 0;
}