【题目描述】
一个整型数组里除了两个数字之外,其他数字都出现了两次。请写程序找出这两个只出现一次的数字。要求时间复杂度为O(n),空间复杂度为O(1)。
【解决方案】
1 public static void FindNumsAppearOnce(int[] data) 2 { 3 if (data == null || data.Length < 1) 4 throw new Exception("Arraty is empty!"); 5 6 int numA = 0, numB = 0, numAll = 0; 7 8 foreach (int num in data) 9 numAll ^= num; 10 11 int bitOneFlag = GetBitOneFlag(numAll); 12 13 foreach (int num in data) 14 { 15 if ((num & bitOneFlag) == 1) 16 numA ^= num; 17 else 18 numB ^= num; 19 } 20 21 Console.WriteLine("numA:{0},numB:{1}", numA, numB); 22 } 23 24 public static int GetBitOneFlag(int num) 25 { 26 int count = 0; 27 28 while ((num & 1 << count) == 0) 29 count++; 30 31 return 1 << count; 32 }
时间: 2024-10-10 17:12:28