NOI2003 文本编辑器editor

1507: [NOI2003]Editor

Time Limit: 5 Sec  Memory Limit: 162 MB
Submit: 1908  Solved: 738
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Description

Input

输入文件editor.in的第一行是指令条数t，以下是需要执行的t个操作。其中： 为了使输入文件便于阅读，Insert操作的字符串中可能会插入一些回车符，请忽略掉它们（如果难以理解这句话，可以参考样例）。 除了回车符之外，输入文件的所有字符的ASCII码都在闭区间[32, 126]内。且行尾没有空格。 这里我们有如下假定： ? MOVE操作不超过50000个，INSERT和DELETE操作的总个数不超过4000，PREV和NEXT操作的总个数不超过200000。 ? 所有INSERT插入的字符数之和不超过2M（1M=1024*1024），正确的输出文件长度不超过3M字节。 ? DELETE操作和GET操作执行时光标后必然有足够的字符。MOVE、PREV、NEXT操作必然不会试图把光标移动到非法位置。 ? 输入文件没有错误。 对C++选手的提示：经测试，最大的测试数据使用fstream进行输入有可能会比使用stdio慢约1秒。

Output

输出文件editor.out的每行依次对应输入文件中每条GET指令的输出。

Sample Input

15
Insert 26
abcdefghijklmnop
qrstuv wxy
Move 16
Delete 11
Move 5
Insert 1
^
Next
Insert 1
_
Next
Next
Insert 4
.\/.
Get 4
Prev
Insert 1
^
Move 0
Get 22

Sample Output

.\/.
abcde^_^f.\/.ghijklmno

HINT

Source

题解：

我靠。。。

刚开始WA,后来栈溢出，然后TLE，还让不让人活了。。。

代码：

1.递归，中序遍历输出结果

  1 {$inline on}
  2 {$M 10000000,0,maxlongint}
  3 const maxn=2000000+1000;
  4 var s,fa:array[0..maxn] of longint;
  5     v:array[0..maxn] of char;
  6     c:array[0..maxn,0..1] of longint;
  7     i,j,n,m,x,y,z,tot,rt,now,l,r:longint;
  8     ch:char;
  9     st,st2:ansistring;
 10 procedure pushup(x:longint);inline;
 11  begin
 12   s[x]:=s[c[x,0]]+s[c[x,1]]+1;
 13  end;
 14 procedure rotate(x:longint;var k:longint);inline;
 15  var y,z,l,r:longint;
 16  begin
 17   y:=fa[x];z:=fa[y];
 18   l:=ord(c[y,1]=x);r:=l xor 1;
 19   if y=k then k:=x else c[z,ord(c[z,1]=y)]:=x;
 20   fa[x]:=z;fa[y]:=x;fa[c[x,r]]:=y;
 21   c[y,l]:=c[x,r];c[x,r]:=y;
 22   pushup(y);pushup(x);
 23  end;
 24 procedure splay(x:longint;var k:longint);inline;
 25  var y,z:longint;
 26  begin
 27   while x<>k do
 28    begin
 29     y:=fa[x];z:=fa[y];
 30     if y<>k then
 31      if (c[z,0]=y) xor (c[y,0]=x) then rotate(x,k)
 32      else rotate(y,k);
 33     rotate(x,k);
 34    end;
 35  end;
 36 function find(x,rank:longint):longint;inline;
 37  var l,r:longint;
 38  begin
 39   l:=c[x,0];r:=c[x,1];
 40   if s[l]+1=rank then exit(x)
 41   else if s[l]>=rank then exit(find(l,rank))
 42   else exit(find(r,rank-s[l]-1));
 43  end;
 44 procedure print(x:longint);inline;
 45  begin
 46   if x=0 then exit;
 47   print(c[x,0]);
 48   write(v[x]);
 49   print(c[x,1]);
 50  end;
 51
 52 procedure main;
 53  begin
 54   readln(n);
 55   l:=maxn-100+1;r:=maxn-100+2;
 56   rt:=l;
 57   c[l,1]:=r;fa[r]:=l;s[l]:=2;s[r]:=1;
 58   now:=1;tot:=0;
 59   for i:=1 to n do
 60    begin
 61     read(ch);
 62     case ch of
 63     ‘P‘:begin
 64         readln;
 65         dec(now);
 66         end;
 67     ‘N‘:begin
 68         readln;
 69         inc(now);
 70         end;
 71     ‘M‘:begin
 72         while ch<>‘ ‘ do read(ch);readln(x);
 73         now:=x+1;
 74         end;
 75     ‘I‘:begin
 76         while ch<>‘ ‘ do read(ch);readln(m);
 77         readln(st);while length(st)<m do begin readln(st2);st:=st+st2;end;
 78         for j:=1 to m do begin inc(tot);fa[tot]:=tot-1;v[tot]:=st[j];s[tot]:=m-j+1;c[tot,0]:=0;if j<>m then c[tot,1]:=tot+1 else c[tot,1]:=0;end;
 79         x:=find(rt,now);y:=find(rt,now+1);
 80         splay(x,rt);splay(y,c[x,1]);
 81         c[y,0]:=tot-m+1;fa[tot-m+1]:=y;
 82         pushup(y);pushup(x);
 83         end;
 84     ‘D‘:begin
 85         while ch<>‘ ‘ do read(ch);readln(m);
 86         x:=find(rt,now);y:=find(rt,now+m+1);
 87         splay(x,rt);splay(y,c[x,1]);
 88         z:=c[y,0];fa[z]:=0;c[y,0]:=0;
 89         pushup(y);pushup(x);
 90         end;
 91     ‘G‘:begin
 92         while ch<>‘ ‘ do read(ch);readln(m);
 93         x:=find(rt,now);y:=find(rt,now+m+1);
 94         splay(x,rt);splay(y,c[x,1]);
 95         print(c[y,0]);writeln;
 96         end;
 97     end;
 98    end;
 99  end;
100 begin
101   assign(input,‘input.txt‘);assign(output,‘output.txt‘);
102   reset(input);rewrite(output);
103   main;
104   close(input);close(output);
105 end.

2.人工栈

  1 {$inline on}
  2 {$M 1000000000,0,maxlongint}
  3 const maxn=2000000+1000;
  4 var s,fa:array[0..maxn] of longint;
  5     v:array[0..maxn] of char;
  6     c:array[0..maxn,0..1] of longint;
  7     i,j,n,m,x,y,z,tot,rt,now,l,r,top:longint;
  8     ch:char;
  9     sta:array[0..maxn*3] of record a,b:longint;end;
 10     st,st2:ansistring;
 11     function min(x,y:longint):longint;inline;
 12      begin
 13       if x<y then exit(x) else exit(y);
 14      end;
 15 procedure pushup(x:longint);inline;
 16  begin
 17   s[x]:=s[c[x,0]]+s[c[x,1]]+1;
 18  end;
 19 procedure rotate(x:longint;var k:longint);inline;
 20  var y,z,l,r:longint;
 21  begin
 22   y:=fa[x];z:=fa[y];
 23   l:=ord(c[y,1]=x);r:=l xor 1;
 24   if y=k then k:=x else c[z,ord(c[z,1]=y)]:=x;
 25   fa[x]:=z;fa[y]:=x;fa[c[x,r]]:=y;
 26   c[y,l]:=c[x,r];c[x,r]:=y;
 27   pushup(y);pushup(x);
 28  end;
 29 procedure splay(x:longint;var k:longint);inline;
 30  var y,z:longint;
 31  begin
 32   while x<>k do
 33    begin
 34     y:=fa[x];z:=fa[y];
 35     if y<>k then
 36      if (c[z,0]=y) xor (c[y,0]=x) then rotate(x,k)
 37      else rotate(y,k);
 38     rotate(x,k);
 39    end;
 40  end;
 41 procedure print(x:longint);
 42  var i,j:longint;
 43  begin
 44   top:=1;sta[top].a:=x;sta[top].b:=1;
 45   while top>0 do
 46     begin
 47      i:=sta[top].a;j:=sta[top].b;dec(top);
 48      if j=2 then write(v[i])
 49      else
 50        begin
 51          if c[i,1]>0 then
 52            begin
 53              inc(top);sta[top].a:=c[i,1];sta[top].b:=1;
 54            end;
 55          inc(top);sta[top].a:=i;sta[top].b:=2;
 56          if c[i,0]>0 then
 57            begin
 58              inc(top);sta[top].a:=c[i,0];sta[top].b:=1;
 59            end;
 60        end;
 61     end;
 62  end;
 63
 64 function find(x,rank:longint):longint;inline;
 65  var l,r:longint;
 66  begin
 67   l:=c[x,0];r:=c[x,1];
 68   if s[l]+1=rank then exit(x)
 69   else if s[l]>=rank then exit(find(l,rank))
 70   else exit(find(r,rank-s[l]-1));
 71  end;
 72 procedure main;
 73  begin
 74   readln(n);
 75   l:=maxn-100+1;r:=maxn-100+2;
 76   rt:=l;
 77   c[l,1]:=r;fa[r]:=l;s[l]:=2;s[r]:=1;
 78   now:=1;tot:=0;
 79   for i:=1 to n do
 80    begin
 81     read(ch);
 82     case ch of
 83     ‘P‘:begin
 84         readln;
 85         dec(now);
 86         end;
 87     ‘N‘:begin
 88         readln;
 89         inc(now);
 90         end;
 91     ‘M‘:begin
 92         while ch<>‘ ‘ do read(ch);readln(x);
 93         now:=x+1;
 94         end;
 95     ‘I‘:begin
 96         while ch<>‘ ‘ do read(ch);readln(m);
 97         readln(st);while length(st)<m do begin readln(st2);st:=st+st2;end;
 98         for j:=1 to m do begin inc(tot);fa[tot]:=tot-1;v[tot]:=st[j];s[tot]:=m-j+1;c[tot,0]:=0;if j<>m then c[tot,1]:=tot+1 else c[tot,1]:=0;end;
 99         x:=find(rt,now);y:=find(rt,now+1);
100         splay(x,rt);splay(y,c[x,1]);
101         c[y,0]:=tot-m+1;fa[tot-m+1]:=y;
102         pushup(y);pushup(x);
103         end;
104     ‘D‘:begin
105         while ch<>‘ ‘ do read(ch);readln(m);
106         x:=find(rt,now);y:=find(rt,min(tot+2,now+m+1));
107         splay(x,rt);splay(y,c[x,1]);
108         z:=c[y,0];fa[z]:=0;c[y,0]:=0;
109         pushup(y);pushup(x);
110         end;
111     ‘G‘:begin
112         while ch<>‘ ‘ do read(ch);readln(m);
113         x:=find(rt,now);y:=find(rt,min(tot+2,now+m+1));
114         splay(x,rt);splay(y,c[x,1]);
115         print(c[y,0]);writeln;
116         end;
117     end;
118    end;
119  end;
120 begin
121   assign(input,‘input.txt‘);assign(output,‘output.txt‘);
122   reset(input);rewrite(output);
123   main;
124   close(input);close(output);
125 end.                              

NOI2003 文本编辑器editor