11.一个游戏，前20关是每一关自身的分数，1-30关每一关是10分，31-40关，每一关是20分，1-49关，每一关是30分，第50关是100分，输入你现在闯到的关卡数，求你现在拥有的分数。利用if嵌套for。
Console.Write("请输入你的关数");
int a = int.Parse(Console.ReadLine());
int sum = 0;
if (a > 0 && a <= 50)
{
if (a > 0 && a <= 20)
{
for (int i = 0; i < a; i++)
{
sum += i;
}
}
else if (a >= 21 && a <= 30)
{
for (int i = 0; i <= 20; i++)
{
sum += i;
}
for (int i = 21; i <= a; i++)
{
sum += 10;
}
}
else if (a >= 31 && a <= 40)
{
for (int i = 0; i <= 20; i++)
{
sum += i;
}
for (int i = 21; i <= 30; i++)
{
sum += 10;
}
for (int i = 31; i <= a; i++)
{
sum += 20;
}
}
else if (a >= 41 && a <= 49)
{
for (int i = 0; i <= 20; i++)
{
sum += i;
}
for (int i = 21; i <= 30; i++)
{
sum += 10;
}
for (int i = 31; i <= 40; i++)
{
sum += 20;
}
for (int i = 41; i <= a; i++)
{
sum += 30;
}
}
else if (a == 50)
{
for (int i = 0; i <= 20; i++)
{
sum += i;
}
for (int i = 21; i <= 30; i++)
{
sum += 10;
}
for (int i = 31; i <= 40; i++)
{
sum += 20;
}
for (int i = 41; i <= 49; i++)
{
sum += 30;
}
sum += 100;
}
Console.WriteLine(sum);
}
else
{
Console.WriteLine("输入有误");
}
Console.ReadLine();
12.一个游戏，前20关是每一关自身的分数，1-30关每一关是10分，31-40关，每一关是20分，1-49关，每一关是30分，第50关是100分，输入你现在闯到的关卡数，求你现在拥有的分数。利用for嵌套if。
Console.Write("请输入你的关数");
int a = int.Parse(Console.ReadLine());
int sum = 0;
if (a > 0 && a <= 50)
{
for (int i = 0; i < a; i++)
{
if (i > 0 && i <= 20)
{
sum += i;
}
else if (i >= 21 && i <= 30)
{
sum += 10;
}
else if (i >= 31 && i <= 40)
{
sum += 20;
}
else if (i >= 41 && i <= 49)
{
sum += 30;
}
else
{
sum += 100;
}
}
Console.WriteLine(sum);
}
else
{
Console.WriteLine("输入有误");
}
Console.ReadLine();
13.输入月份和日期，输出是今年的第多少天。（2月按照28天计算）利用switch case。
int m1 = 31, m2 = 28, m3 = 31, m4 = 30, m5 = 31, m6 = 30, m7 = 31, m8 = 31, m9 = 30, m10 = 31, m11 = 30;
Console.Write("请输入月份");
int m = int.Parse(Console.ReadLine());
Console.Write("请输入日期");
int d = int.Parse(Console.ReadLine());
switch (m)
{
case 1:
Console.WriteLine("第" + d + "天");
break;
case 2:
Console.WriteLine("第" + (m1 + d) + "天");
break;
case 3:
Console.WriteLine("第" + (m1 + m2 + d) + "天");
break;
case 4:
Console.WriteLine("第" + (m1 + m2 + m3 + d) + "天");
break;
case 5:
Console.WriteLine("第" + (m1 + m2 + m3 + m4 + d) + "天");
break;
case 6:
Console.WriteLine("第" + (m1 + m2 + m3 + m4 + m5 + d) + "天");
break;
case 7:
Console.WriteLine("第" + (m1 + m2 + m3 + m4 + m5 + m6 + d) + "天");
break;
case 8:
Console.WriteLine("第" + (m1 + m2 + m3 + m4 + m5 + m6 + m7 + d) + "天");
break;
case 9:
Console.WriteLine("第" + (m1 + m2 + m3 + m4 + m5 + m6 + m7 + m8 + d) + "天");
break;
case 10:
Console.WriteLine("第" + (m1 + m2 + m3 + m4 + m5 + m6 + m7 + m8 + m9 + d) + "天");
break;
case 11:
Console.WriteLine("第" + (m1 + m2 + m3 + m4 + m5 + m6 + m7 + m8 + m9 + m10 + d) + "天");
break;
case 12:
Console.WriteLine("第" + (m1 + m2 + m3 + m4 + m5 + m6 + m7 + m8 + m9 + m10 + m11 + d) + "天");
break;
}
Console.ReadLine();
14.百鸡百钱：公鸡2文钱一只，母鸡1文钱一只，小鸡半文钱一只，总共只有100文钱，如何在凑够100只鸡的情况下刚好花完100文钱？利用for嵌套+if筛选。
int biao = 0;
for (int g = 0; 2 * g <= 100; g++)
{
for (int m = 0; m <= 100; m++)
{
for (int x = 0; 0.5 * x <= 100; x++)
{
if (2 * g + m + 0.5 * x == 100 && g + m + x == 100)
{
biao++;
Console.WriteLine("第" + biao + "种共有公鸡" + g + "只，母鸡" + m + "只，小鸡" + x + "只");
}
}
}
}
Console.WriteLine("一共有" + biao + "种");
Console.ReadLine();
15.大马驼2石粮食，中等马驼1石粮食，两头小马驼1石粮食，要用100匹马，驼100石粮食，该如何分配？利用for嵌套+if筛选。
for (int x = 0; x <= 50; x++)
{
for (int y = 0; y <= 100; y++)
{
for (int z = 0; z <= 200; z++)
{
if (x + y + z == 100 && 2 * x + y + 0.5 * z == 100)
{
Console.WriteLine("有大马" + x + "匹，中等马" + y + "匹，小马" + z + "匹");
}
}
}
}
Console.ReadLine();
16.纸张可以无限次对折，纸张厚度为0.07毫米。问多少次对折至少可以超过8848？利用while。
int i = 0;
int a = 7;
while (a <= 884800000)
{
a *= 2;
i++;
}
Console.WriteLine(a);
Console.WriteLine(i);
Console.ReadLine();
17.兔子生兔子。除了第一个月之后的所有月份都可以直接执行。成兔=上个月的成兔加上上个月的小兔。小兔=上个月的幼兔。幼兔=上个月的成兔加上上个月的小兔（即这个月的成兔）利用for嵌套if。
Console.Write("请输入月份");
int a = int.Parse(Console.ReadLine());
int y = 1;
int x = 0;
int c = 0;
int zong = 0;
for (int i = 0; i <= a; i++)
{
if (i == 1)
{
y = 1;
x = 0;
c = 0;
zong = 1;
}
else
{
c = x + c;
x = y;
y = c;
zong = x + y + c;
}
}
Console.WriteLine("第" + a + "个月共" + zong + "对,有幼兔" + y + "对，小兔" + x + "对，成兔" + c + "对");
Console.ReadLine();
19.五个候选班长，20人投票。输入1-5来表示支持哪（个人）最后查看票数，看那个人胜出。不是1~5之内的数视为票作废。利用数组。
string[]shuzu=new string[20];
int sum1 = 0, sum2 = 0, sum3 = 0, sum4 = 0, sum5 = 0;
for (int i = 0; i < 20; i++)
{
Console.Write("第"+(i+1)+"个人支持的号码是：");
shuzu[i] = Console.ReadLine();
if (shuzu[i] =="1")
{
sum1++;
}
else if (shuzu[i] == "2")
{
sum2++;
}
else if (shuzu[i] == "3")
{
sum3++;
}
else if (shuzu[i] == "4")
{
sum4++;
}
else if (shuzu[i] == "5")
{
sum5++;
}
else
{
Console.WriteLine("输入有误作废");
}
}
Console.WriteLine("所有人都已选择完毕");
Console.WriteLine("1号选手得票数："+sum1);
Console.WriteLine("2号选手得票数：" + sum2);
Console.WriteLine("3号选手得票数：" + sum3);
Console.WriteLine("4号选手得票数：" + sum4);
Console.WriteLine("5号选手得票数：" + sum5);
if (sum1 > sum2 && sum1 > sum3 && sum1 > sum4 && sum1 > sum5)
{
Console.WriteLine("1号选手获胜");
}
else if (sum2> sum1 && sum2 > sum3 && sum2 > sum4 && sum2 > sum5)
{
Console.WriteLine("2号选手获胜");
}
else if (sum3 > sum2 && sum3 > sum1 && sum3 > sum4 && sum3 > sum5)
{
Console.WriteLine("3号选手获胜");
}
else if (sum4 > sum1 && sum4 > sum3 && sum4 > sum2 && sum4 > sum5)
{
Console.WriteLine("4号选手获胜");
}
else
{
Console.WriteLine("5号选手获胜");
}
Console.ReadLine();
20.输入手机号码个数，根据手机号码个数创建数组。做抽奖活动。利用System.Threading.Thread.Sleep(3000);//程序暂停3秒
Console.Write("请输入电话号码的个数");
int n = int.Parse(Console.ReadLine());
string[] shuzu = new string[n];//把这n个手机号放到数组中
for (int i = 0; i < n; i++)
{
Console.Write("第" + (i + 1) + "个人的手机号是");
shuzu[i] = Console.ReadLine();//接受数组
}
Console.WriteLine("所有号码输入完毕，按回车");
Console.ReadLine();
Random ran = new Random();//初始化
int m = 0;
for (; ; )
{
int nn = ran.Next(n);//随机从n中抽取
Console.Clear();//清屏
Console.WriteLine(shuzu[nn]);
System.Threading.Thread.Sleep(100);//100毫秒
if (m == 29) //0.1*30=3秒
{
break;
}
m++;
}
Console.ReadLine();
时间： 2024-12-28 14:31:11