python购物车小案例

python购物车小案例#     案列描述：有一个小型水果店里面有水果（苹果：¥8/kg，香蕉：¥5/kg，芒果：¥15/kg，葡萄：¥12/kg），客户带了100元钱进店选购水果。#             1.客户输入相应序号和对应数量后将该商品加入购物车#             2.付款时检查客户是否有支付能力（结算金额<=100）#             3.客户输入Q/q退出选购

lis = [{‘name‘: ‘苹果‘, ‘price‘: 8},
       {‘name‘: ‘香蕉‘, ‘price‘: 5},
       {‘name‘: ‘芒果‘, ‘price‘: 15},
       {‘name‘: ‘葡萄‘, ‘price‘: 12}]
moeny = input(‘请输入充值金额：‘)
for i, v in enumerate(lis):
    print(‘序号：{}，商品：{}，价格：{}‘.format(i + 1, v[‘name‘], v[‘price‘]))
shopping = {}
flag = True
while flag:
    chooes = input(‘请输入选择的商品序号（输入Q/q退出）：‘)
    if chooes.isdigit() and int(chooes) <= len(lis):
        while 1:
            unmber = input(‘请输入需要购买的数量(输入Q/q退出)：‘)
            if unmber.isdigit():
                name = lis[int(chooes) - 1][‘name‘]
                v = 0
                if shopping.get(name, ‘no‘) == ‘no‘:
                    shopping[name] = unmber
                else:
                    v = int(shopping[name])
                    unmber = int(unmber) + v
                    shopping[name] = unmber
                print(‘---添加购物车成功---‘)
                print(‘您购买的是：{}，数量为：{}‘.format(name, int(unmber) - v))
                see_shopping = input(‘---输入Y/y/1查看购物车或结算，其他任意键继续选购---‘)
                if see_shopping == ‘Y‘ or see_shopping == ‘y‘ or see_shopping == ‘1‘:
                    for name, number in shopping.items():
                        print(‘您的购物车里面有：{}，数量：{}‘.format(name, number))
                        #未进行结算
                else:
                    break
                break
            elif unmber == ‘Q‘ or unmber == ‘q‘:
                flag = False
                break
            else:
                print(‘输入有误，请重新输入。‘)

    elif chooes == ‘Q‘ or chooes == ‘q‘:
        break
    else:
        print(‘输入有误，请重新输入。‘)
print(‘---程序已退出---‘)

原文地址：https://www.cnblogs.com/zhuzl/p/11135303.html