Black Box
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 10658 | Accepted: 4390 |
Description
Our Black Box represents a primitive database. It can save an integer array and has a special i variable. At the initial moment Black Box is empty and i equals 0. This Black Box processes a sequence of commands (transactions). There are two types of transactions:
ADD (x): put element x into Black Box;
GET: increase i by 1 and give an i-minimum out of all integers
containing in the Black Box. Keep in mind that i-minimum is a number
located at i-th place after Black Box elements sorting by non-
descending.
Let us examine a possible sequence of 11 transactions:
Example 1
N Transaction i Black Box contents after transaction Answer
(elements are arranged by non-descending)
1 ADD(3) 0 3
2 GET 1 3 3
3 ADD(1) 1 1, 3
4 GET 2 1, 3 3
5 ADD(-4) 2 -4, 1, 3
6 ADD(2) 2 -4, 1, 2, 3
7 ADD(8) 2 -4, 1, 2, 3, 8
8 ADD(-1000) 2 -1000, -4, 1, 2, 3, 8
9 GET 3 -1000, -4, 1, 2, 3, 8 1
10 GET 4 -1000, -4, 1, 2, 3, 8 2
11 ADD(2) 4 -1000, -4, 1, 2, 2, 3, 8
It is required to work out an efficient algorithm which treats a given sequence of transactions. The maximum number of ADD and GET transactions: 30000 of each type.
Let us describe the sequence of transactions by two integer arrays:
1. A(1), A(2), ..., A(M): a sequence of elements which are being included into Black Box. A values are integers not exceeding 2 000 000 000 by their absolute value, M <= 30000. For the Example we have A=(3, 1, -4, 2, 8, -1000, 2).
2. u(1), u(2), ..., u(N): a sequence setting a number of elements which are being included into Black Box at the moment of first, second, ... and N-transaction GET. For the Example we have u=(1, 2, 6, 6).
The Black Box algorithm supposes that natural number sequence u(1), u(2), ..., u(N) is sorted in non-descending order, N <= M and for each p (1 <= p <= N) an inequality p <= u(p) <= M is valid. It follows from the fact that for the p-element of our u sequence we perform a GET transaction giving p-minimum number from our A(1), A(2), ..., A(u(p)) sequence.
Input
Input contains (in given order): M, N, A(1), A(2), ..., A(M), u(1), u(2), ..., u(N). All numbers are divided by spaces and (or) carriage return characters.
Output
Write to the output Black Box answers sequence for a given sequence of transactions, one number each line.
Sample Input
7 4 3 1 -4 2 8 -1000 2 1 2 6 6
Sample Output
3 3 1 2 水题瞬秒……
1 #include <iostream>
2 #include <cstring>
3 #include <cstdio>
4 #include <queue>
5 using namespace std;
6 const int maxn=100010;
7 int a[maxn],t[maxn],n,m;
8 priority_queue<int>A;
9 priority_queue<int,vector<int>,greater<int> >B;
10 int main(){
11 scanf("%d%d",&n,&m);
12 for(int i=1;i<=n;i++)scanf("%d",&a[i]);
13 for(int i=1;i<=m;i++)scanf("%d",&t[i]);
14 for(int i=1,p=0;i<=m;i++){
15 while(p!=t[i])B.push(a[++p]);
16 while(A.size()<1ul*i){
17 A.push(B.top());
18 B.pop();
19 }
20 while(B.size()&&A.top()>B.top()){
21 A.push(B.top());
22 B.push(A.top());
23 A.pop();B.pop();
24 }
25 printf("%d\n",A.top());
26 }
27 return 0;
28 }