You‘re given strings J
representing the types of stones that are jewels, and S
representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J
are guaranteed distinct, and all characters in J
and S
are letters. Letters are case sensitive, so "a"
is considered a different type of stone from "A"
.
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S
andJ
will consist of letters and have length at most 50.- The characters in
J
are distinct.
class Solution: def numJewelsInStones(self, J, S): """ :type J: str :type S: str :rtype: int """ return len([elem for elem in S if elem in J])
原文地址:https://www.cnblogs.com/chiyeung/p/9650663.html
时间: 2024-11-08 07:18:26