(滑动窗口的最大值)题目描述:
给定一个数组和滑动窗口的大小,找出所有滑动窗口里数值的最大值。例如,如果输入数组{2,3,4,2,6,2,5,1}及滑动窗口的大小3,那么一共存在6个滑动窗口,他们的最大值分别为{4,4,6,6,6,5}; 针对数组{2,3,4,2,6,2,5,1}的滑动窗口有以下6个: {[2,3,4],2,6,2,5,1}, {2,[3,4,2],6,2,5,1}, {2,3,[4,2,6],2,5,1}, {2,3,4,[2,6,2],5,1}, {2,3,4,2,[6,2,5],1}, {2,3,4,2,6,[2,5,1]}。
解决思路:利用一个大顶堆
import java.util.ArrayList; import java.util.PriorityQueue; import java.util.Comparator; public class Solution { //大顶堆,从大到小的排列 private PriorityQueue<Integer> heap=new PriorityQueue<Integer>(15,new Comparator<Integer>(){ @Override public int compare(Integer o1,Integer o2){ return o2-o1; } }); public ArrayList<Integer> maxInWindows(int [] num, int size) { //存放结果集 ArrayList<Integer> result=new ArrayList<Integer>(); if(num==null||num.length==0||num.length<size||size<=0){ return result; } for(int i=0;i<size;i++){ heap.offer(num[i]); } result.add(heap.peek()); //i从1到num.length-size for(int i=1;i<num.length+1-size;i++){ heap.remove(num[i-1]); heap.offer(num[i+size-1]); result.add(heap.peek()); } return result; } }
解决办法二:
import java.util.ArrayList; public class Solution { public ArrayList<Integer> maxInWindows(int [] num, int size) { ArrayList<Integer> result = new ArrayList<Integer>(); if(num == null||size == 0 ||size>num.length){ return result; } int max = num[0];//记录最大值 int index = -1;//记录最大值下标,防止最大值过期 int len = num.length; int plow = 0,phight = size-1;//滑动窗口边界 while(phight<len){//此处不要条件plow<phight,因为有可能size=1 if((index>=plow)&&(index<=phight)){//保证最大值未过期 if(max<num[phight]){ max = num[phight]; index = phight; } }else{ max = num[plow]; index = plow; for(int i=plow;i<=phight;i++){ if(max<num[i]){ max = num[i]; index = i; } } } result.add(max); plow++; phight++; } return result; } }
原文地址:https://www.cnblogs.com/dashenaichicha/p/12540226.html
时间: 2024-10-09 16:58:05