[leetcode]346. Moving Average from Data Stream滑动窗口平均值

Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window.

For example,

MovingAverage m = new MovingAverage(3);
m.next(1) = 1
m.next(10) = (1 + 10) / 2
m.next(3) = (1 + 10 + 3) / 3
m.next(5) = (10 + 3 + 5) / 3

题意：

给定固定长度的滑动窗口，更新滑动窗口中所有数的平均值。

思路：

这种先进先出的特性很适合用queue

若当前queue的size大于sliding window的长度

则从queue中remove一个元素

注意：

全局变量用下划线_size, _sum是个好的coding style

代码：

 1 class MovingAverage {
 2     Queue<Integer> _queue = new LinkedList<>();
 3     int _size;
 4     double _sum;
 5
 6     /** Initialize your data structure here. */
 7     public MovingAverage(int size) {
 8         _size = size;
 9         _sum = 0.0;
10     }
11
12     public double next(int val) {
13         _queue.add(val);
14         _sum = _sum + val;
15         if(_queue.size() > _size ){
16             _sum = _sum - _queue.remove();
17         }
18         return _sum/_queue.size();
19     }
20 }
21
22 /**
23  * Your MovingAverage object will be instantiated and called as such:
24  * MovingAverage obj = new MovingAverage(size);
25  * double param_1 = obj.next(val);
26  */

原文地址：https://www.cnblogs.com/liuliu5151/p/9189707.html