1 /** 2 * Definition for singly-linked list. 3 * public class ListNode { 4 * int val; 5 * ListNode next; 6 * ListNode(int x) { 7 * val = x; 8 * next = null; 9 * } 10 * } 11 */ 12 public class Solution { 13 public ListNode mergeKLists(List<ListNode> lists) { 14 ListNode head=new ListNode(-1); 15 ListNode tail=head; 16 if(lists.size()<=0) return null; 17 Comparator<ListNode> mycmp=new Comparator<ListNode>() 18 { 19 public int compare(ListNode l1,ListNode l2) 20 { 21 if(l1.val>l2.val) return 1; 22 else if(l1.val<l2.val)return -1; 23 return 0; 24 25 26 27 } 28 29 } ; 30 31 PriorityQueue<ListNode> prq=new PriorityQueue<ListNode>(lists.size(),mycmp); 32 for(ListNode n:lists) 33 { 34 if(n!=null) 35 { 36 prq.add(n); 37 } 38 39 } 40 while(prq.size()>0) 41 { 42 ListNode tem=prq.poll(); 43 tail.next=tem; 44 tail=tail.next; 45 if(tem.next!=null) 46 { 47 prq.add(tem.next); 48 } 49 50 51 } 52 53 return head.next; 54 55 56 57 58 59 } 60 }
(java) Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.
时间: 2024-10-29 11:50:02