leetCode 58.Length of Last Word (最后单词的长度) 解题思路和方法

Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,

Given s = "Hello World",

return 5.

思路：题目非常简单，没什么好说的，唯一要注意的就是后面的结尾可能很多空格。

具体代码如下：

public class Solution {
    public int lengthOfLastWord(String s) {
        int len = 0;
        boolean isEmpty = false;//从后往前数，直到不是空格
        for(int i = s.length()-1; i > -1; i--){
            if(s.charAt(i) != ' '){
                len++;
                isEmpty = true;
            }else if(isEmpty){//倒数第二个空格出现
                return len;
            }
        }
        return len;
    }
}

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