139. Word Break（js）

139. Word Break

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

Note:

• The same word in the dictionary may be reused multiple times in the segmentation.
• You may assume the dictionary does not contain duplicate words.

Example 1:

Input: s = "leetcode", wordDict = ["leet", "code"]
Output: true
Explanation: Return true because "leetcode" can be segmented as "leet code".

Example 2:

Input: s = "applepenapple", wordDict = ["apple", "pen"]
Output: true
Explanation: Return true because "applepenapple" can be segmented as "apple pen apple".
             Note that you are allowed to reuse a dictionary word.

Example 3:

Input: s = "catsandog", wordDict = ["cats", "dog", "sand", "and", "cat"]
Output: false题意：能否在wordDict中抽出几个单词(可以重复抽取)拼凑成s代码如下：

/**
 * @param {string} s
 * @param {string[]} wordDict
 * @return {boolean}
 */
var wordBreak = function(s, wordDict) {
    var tmp=[];
    for(var i=0;i<s.length+1;i++){
        if(i===0) tmp[i]=true;
        else tmp[i]=false;
    }

    for(var i=1;i<=s.length;i++){
        for(var j=0;j<i;j++){
            if(tmp[j] && wordDict.includes(s.substring(j,i))){
                tmp[i]=true;
                break;
            }

        }
    }
    return tmp[s.length];
};

原文地址：https://www.cnblogs.com/xingguozhiming/p/10986765.html