| Time Limit: 1000MS | Memory Limit: 262144KB | 64bit IO Format: %I64d & %I64u |
Description
The prison of your city has n prisoners. As the prison can‘t accommodate all of them, the city mayor has decided to transfer c of the prisoners to a prison located in another city.
For this reason, he made the n prisoners to stand in a line, with a number written on their chests. The number is the severity of the crime he/she has committed. The greater the number, the more severe his/her crime was.
Then, the mayor told you to choose the c prisoners, who will be transferred to the other prison. He also imposed two conditions. They are,
- The chosen c prisoners has to form a contiguous segment of prisoners.
- Any of the chosen prisoner‘s crime level should not be greater then t. Because, that will make the prisoner a severe criminal and the mayor doesn‘t want to take the risk of his running away during the transfer.
Find the number of ways you can choose the c prisoners.
Input
The first line of input will contain three space separated integers n (1 ≤ n ≤ 2·105), t (0 ≤ t ≤ 109) and c (1 ≤ c ≤ n). The next line will contain n space separated integers, the ith integer is the severity ith prisoner‘s crime. The value of crime severities will be non-negative and will not exceed 109.
Output
Print a single integer — the number of ways you can choose the c prisoners.
Sample Input
Input
4 3 32 3 1 1
Output
2
Input
1 1 12
Output
0
Input
11 4 22 2 0 7 3 2 2 4 9 1 4
Output
6
Source
Codeforces Round #244 (Div. 2)
模拟题
#include <iostream>
#include <algorithm>
#include <string.h>
#include <stdlib.h>
#include <math.h>
#include <stdio.h>
using namespace std;
int a[200050];
int main()
{
int i,j,n,t,c,flag=0,ans=0;
scanf("%d%d%d",&n,&t,&c);
for(i=0;i<n;i++)
cin>>a[i];
for(i=0;i<n;i++)
{
if (a[i]>t)
{
if(flag>=c)
ans=ans+flag-c+1;
flag=0;
}
else if(a[i]<=t)
flag=flag+1;
}
if(flag>=c)
ans=ans+flag-c+1;
printf("%d\n",ans);
return 0;
}